Finding energy payback period
As you prepare to close the books on 2011, it’s never too soon to start planning for next year. When you look around the farmstead, how many “projects” can you see?
Farm projects are a lot like utility meters, always turning. Whether your plans include new construction, replacing motors or equipment, or upgrading lighting systems, now is the time to make decisions about where to reinvest your farm business dollars. Safeguarding yourself against rising energy prices can start with comparing the simple payback for energy-related farm projects.
“Saving money today by purchasing equipment with a lower initial cost and higher energy demands puts the buyer at risk when energy prices rise in the future,” says Mark Hanna, ISU Extension ag engineer. “This can potentially negate the savings associated with the low purchase price.”
Calculating the payback period for a purchase means dividing the initial cost by the projected annual energy savings. For example, if the cost for new equipment is $3,600 and the projected annual energy savings at current energy prices is $900, the initial cost is repaid through energy savings after four years ($3,600/$900 = 4).
Simple payback is typically helpful for comparing purchases with relatively short payback periods. However, this method does not account for continued energy savings (return on investment) after a project reaches its breakeven point.
To do this, you need reliable information about the equipment’s useful life. Some examples illustrating the benefits and limitations of the simple payback method are available in the latest ISU Farm Energy fact sheet, “Estimating Payback for Energy Efficiency,” PM 2089S, at farmenergy.exnet.iastate.edu.
• Lighting. Initial cost to replace bulbs in a livestock facility is $400, but the projected annual electrical savings is $2,000. The simple payback period is 0.2 years ($400/$2,000) with a savings of $1,600 in year one and $2,000 in year two. Estimated bulb life for the project is two years, so return on investment is $3,600 over two years. Extra labor costs may be incurred to make the switch to new light bulbs or fixtures, but consider if the energy savings from the upgraded, energy-efficient lighting will cover labor and installation costs.
• 10-horsepower electric motor. A 10-hp electric motor is being used 10 hours per week to grind feed. A new replacement motor is estimated to save 1 kilowatt of energy during each hour of operation, saving 10 kWh each week, or 520 kWh annually. Assuming electricity costs 10 cents per kWh, annual cost savings are $52. If replacement cost for a 10-hp motor is $1,000 on average, the simple payback is 19.2 years ($1,000/$52). Thus, if economics are the only factor, replacement would likely be delayed until the end of the motor’s life.
• Pickup truck. The existing farm truck has an estimated fuel efficiency of 15 mpg, but a late-model truck gets about 25 mpg and is available for $15,000, plus trade-in. Assuming 18,000 annual mileage, the newer truck would consume 720 gallons (18,000/25) of fuel versus 1,200 gallons (18,000/15) for the existing truck. At fuel prices of $3 per gallon, the extra 480 gallons of fuel conserved equals $1,440 annually. The simple payback period is 10.4 years ($15,000/$1,440). However, at increased fuel costs of $4 per gallon, the simple payback is 7.8 years ($15,000/$1,920).
As shown, simple payback is helpful for estimating how long it will take to recoup your investment, but it doesn’t show profitability. When only energy costs are considered, purchases with a long payback may not pay for themselves until they’re nearly worn out. Unless your goal is to quickly recoup funds and put them to work again, look beyond the simple payback. Consider the total cost, useful life, maintenance and energy savings of a purchase to determine if it’s a wise investment.
Petersen is program coordinator for the ISU Farm Energy Initiative.
This article published in the December, 2011 edition of WALLACES FARMER.
All rights reserved. Copyright Farm Progress Cos. 2011.